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Syd chooses two different primes, and multiplies them.  If both primes are greater than $20$, and the resulting product is less than $2000$, then how many different products could Syd have ended up with?

 Feb 15, 2024

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 #2
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Sry but,

I just saw the answer in the link you have sent and I got a different answer. So here is what I did:

23 is the smallest prime \(>20\) and all different primes till 83 satisfy the condition. This is 14 primes

similarly 29 matches with 9 primes(till 67), 31 with 6 (till 59), 37 with 4(till 53), and lastly 41 with 2(till 47).

This is a total of \(\boxed{35}\) different products as all the numbers have a different pair prime factors.

 Feb 15, 2024
 #1
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Here :  https://web2.0calc.com/questions/help-plz_85848

 

cool cool cool

 Feb 15, 2024
 #2
avatar
+1
Best Answer

Sry but,

I just saw the answer in the link you have sent and I got a different answer. So here is what I did:

23 is the smallest prime \(>20\) and all different primes till 83 satisfy the condition. This is 14 primes

similarly 29 matches with 9 primes(till 67), 31 with 6 (till 59), 37 with 4(till 53), and lastly 41 with 2(till 47).

This is a total of \(\boxed{35}\) different products as all the numbers have a different pair prime factors.

EnormousBighead  Feb 15, 2024

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