Syd chooses two different primes, and multiplies them. If both primes are greater than $20$, and the resulting product is less than $2000$, then how many different products could Syd have ended up with?
Sry but,
I just saw the answer in the link you have sent and I got a different answer. So here is what I did:
23 is the smallest prime \(>20\) and all different primes till 83 satisfy the condition. This is 14 primes
similarly 29 matches with 9 primes(till 67), 31 with 6 (till 59), 37 with 4(till 53), and lastly 41 with 2(till 47).
This is a total of \(\boxed{35}\) different products as all the numbers have a different pair prime factors.
Sry but,
I just saw the answer in the link you have sent and I got a different answer. So here is what I did:
23 is the smallest prime \(>20\) and all different primes till 83 satisfy the condition. This is 14 primes
similarly 29 matches with 9 primes(till 67), 31 with 6 (till 59), 37 with 4(till 53), and lastly 41 with 2(till 47).
This is a total of \(\boxed{35}\) different products as all the numbers have a different pair prime factors.