+625 Four children and four adults are to be seated at a circular table. In how many different ways can they be seated if all the children are next to each other, and all the adults are next to each other? (Two seatings are considered the same if one can be rotated to form the other.)
+1804 Let's calculate the number of ways we can seat the children and adults seperately.
First, there are \(4! = 24\) ways to seat the children and \(4! = 24\) ways to seat the adults.
We now multiply these values together to get
\(24*24=576\)
So 576 is our answer.
Thanks! :)
