How many odd five-digit counting numbers can be formed by choosing digits from the set \(\{1, 2, 3, 4, 5, 6, 7, 8\}\) if digits can be repeated?
+36916 To be odd, the number must end in 1 3 5 or 7 4 choices for the last position
8 choices for each of the other four positions
8 x 8 x 8 x 8 x 4 = .......
