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How many odd five-digit counting numbers can be formed by choosing digits from the set \(\{1, 2, 3, 4, 5, 6, 7, 8\}\)  if digits can be repeated?

 Jan 10, 2022
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To be odd, the number must end in 1 3 5 or 7    4 choices for the last position

   8 choices for each of the other four positions

 

8 x 8 x 8 x 8 x 4 = .......

 Jan 10, 2022

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