+314 A standard six-sided die is rolled $8$ times. You are told that among the rolls, there was two $1$'s, two $2$'s, two $3$'s, and two $4$s. How many possible sequences of rolls could there have been? (For example, $2,$ $1,$ $3,$ $4,$ $2,$ $1$, $3$, $4$ is one possible sequence.)
+37128 There are 8 rolls = 8! = 40320 possible combinatins IF htere were no duplicate numbers
BUT there is two 1's two 2 's two 3's and two 4's so you have to divide that result by 2! 2! 2! 2!
to get 40320 / 16 = 2520 possible sequences
