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How many ways are there to put 4 balls in 3 boxes if the balls are not distinguishable and the boxes are not distinguishable?

 Oct 22, 2022
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With empty boxes allowed, you have:
4 0 0 = 3 permutations
3 1 0 = 6 p
2 2 0 = 3 p
2 1 1 = 3 p

 

Total = 3 + 6 + 3 + 3 = 15 ways

 Oct 22, 2022

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