How many 3-digit numbers contain exactly one 1 and exactly one 2? Examples include 512 and 271.
There are 8 choices for the remaining number (0, 3, 4, 5, 6, 7, 8, 9)
Once we select this number, there are \(3! = 6\) numbers that can be made.
However, we need to subtract 2 because 0 can't be a leading digit.
This makes for \(8 \times 6 - 2 = \color{brown}\boxed{46}\) numbers.
There are 8 choices for the remaining number (0, 3, 4, 5, 6, 7, 8, 9)
Once we select this number, there are \(3! = 6\) numbers that can be made.
However, we need to subtract 2 because 0 can't be a leading digit.
This makes for \(8 \times 6 - 2 = \color{brown}\boxed{46}\) numbers.