2 log ( a - 2b) = log a + log b .....using a coulpe of log properties
log (a - 2b)^2 = log (ab) which implies that
( a - 2b)^2 = ab
a^2 - 4ab + 4b^2 = ab
a^2 - 5ab + 4b^2 = 0 factor as
(a - 4b) ( a - b) = 0
a - 4b = 0 or a - b = 0
a = 4b a = b
a/b = 4 a/b = 1
Assuming a, b are positive ......
The second solution either makes (a -2b) negative and we can't take the log of a negative
So
a/b = 4