Given that \(f(2)=5\) and \(f^{-1}(x+4)=2f^{-1}(x)+1\) for all \(x\) , find \(f^{-1}(17)\).
If f (2) = 5
Then this implies that :
f-1 (5) = 2 ...so....
2f-1 (5) + 1 = f-1 (5 + 4)
2*2 + 1 = f-1 ( 5 + 4)
5 = f-1 (9)
2f-1(9) + 1 = f-1(9 + 4)
2*5 + 1 = f-1(13)
11 = f-1 (13)
2 f-1 (13) + 1 = f-1(13 + 4)
2 * 11 + 1 = f-1 (17)
23 = f-1(17)
+816 
