The solutions to
\(2x^2-10x+13=0\)
are \(a+bi \) and \(a-bi\) where \(a\) and \(b\) are positive. What is \(a \cdot b\)?
Note: I got 13/2, and -5/16, but none of them worked. Help!
+36916 Quadratic Formula a = 2 b= -10 c = 13 yields x = 2.5 +- .5 i 2.5 * .5 = 1.25 or 1 1/4
