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The solutions to

\(2x^2-10x+13=0\)

 

are \(a+bi \) and \(a-bi\) where \(a\) and \(b\) are positive. What is \(a \cdot b\)?

 

Note: I got 13/2, and -5/16, but none of them worked. Help!

 Apr 3, 2020
edited by Guest  Apr 3, 2020
 #1
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Quadratic Formula     a = 2   b= -10    c = 13       yields   x = 2.5 +- .5 i            2.5 * .5 = 1.25    or  1  1/4

 Apr 3, 2020
 #2
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Thank you!!

Guest Apr 4, 2020

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