+0  
 
0
61
1
avatar+41 

Given that $a > 0$, if $f(g(a)) = 8$, where $f(x) = x^2 + 8$ and $g(x) = x^2 - 4$, what is the value of $a$?

 Jul 25, 2021
 #1
avatar+34388 
+1

Start with f(x) = 8          where x , in this case is g(a)

f(x) = 8

x^2 + 8 = 8 

x = 0           rememeber   that x is g(a) in this case,    so   a^2 - 4 =0

 

a^2 - 4 = 0

a^2 = 4

a = +-2

 Jul 25, 2021

33 Online Users

avatar
avatar
avatar