+4 Let ABC be a triangle, and let its angle bisectors be AD, BE, and CF, which intersect at I. If DI = 3, BD = 4, and BI = 5, then compute the area of triangle ABC. Can CPhill or Melody please answer this question with a diagram and preferably no law of sines, or anything like that? Just using angle bisector concepts.
+4 You can find the area of ABC using the formula: Area = (2 * √(s(s-a)(s-b)(s-c))) / (a+b+c), where s is the semiperimeter. Live The Orange Life
