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Let ABC be a triangle, and let its angle bisectors be AD, BE, and CF, which intersect at I. If DI = 3, BD = 4, and BI = 5, then compute the area of triangle ABC. Can CPhill or Melody please answer this question with a diagram and preferably no law of sines, or anything like that? Just using angle bisector concepts.

 Aug 10, 2023
 #1
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You can find a solution here!

 

https://web2.0calc.com/questions/hxlp

 Aug 10, 2023
 #2
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You can find the area of ABC using the formula: Area = (2 * √(s(s-a)(s-b)(s-c))) / (a+b+c), where s is the semiperimeter. Live The Orange Life
 

 Aug 11, 2023

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