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avatar+11912 

V) 4x^2 - 8x + 4

 Jan 18, 2015

Best Answer 

 #4
avatar+11912 
+5

Yeah! I just got the answer!thanks!

gosh somebody take me to a new land! 

 Jan 18, 2015
 #1
avatar+128632 
+5

OK, rosala......

Remember that the first thing we want to do before we ever start factoring is to take out the common factor  (here it's 4)...so we have

4 [x^2 - 2x +1]   .....now let's just factor the expression in the parentheses...we'll go back and tack on the "4" at the end...

So what's the square root of x^2 ???

And what's the square root of 1  ??

And what sign do we use between the terms??

Let me know if this one gives you trouble....it's a little different...

 

 Jan 18, 2015
 #2
avatar+11912 
0

Square root of x^2 is x and 1^2 is 1......... CPhill I have no idea what you are talking about!

 Jan 18, 2015
 #3
avatar+128632 
+5

LOL!!!...you're really close to the answer....!!!

Let me see if I can finish for you...

We have

4 [ x^2 - 2x + 1 ] =        square root of x^2 = x     square root of 1 = 1  ... and those are the two things we want to factor with.....!!!

4 (x - 1) (x -1)  =

4(x -1) ^2

Do you see it, now ??

Don't let that lead "4" fool you...we're just letting it ride along.....!!!

 Jan 18, 2015
 #4
avatar+11912 
+5
Best Answer

Yeah! I just got the answer!thanks!

gosh somebody take me to a new land! 

rosala Jan 18, 2015

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