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Three men went to a hotel to rent a room, the cost of the room was $30. Each man paid $10 to the bellboy and proceeded to their room. After a little while the bellboy realized that there was a special on rooms that night and the price for the men's room should have been $25. On his way to the men's room to give them back $5, he was puzzled how he was going to split $5 as he had no change. He decided he would give them each $1 and keep the remaining $2 for himself. So each man originally paid $10, but after the bellboy gave each man $1 back, each man paid $9. 9 x 3 = $27 plus the $2 the bellboy put in his pocket equals $29. The original price for the room was $30. Where did the last dollar go?

(CAN YOU SOLVE THIS ?) I already know the answer but do you ?

Translated using Bing Translator (Spanish to English)
 Nov 14, 2013
 #1
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1st off, each man paid 10 dollars, then got one back, so that's 27. 27 minus the 2 that he pocketed is 25. Where's the riddle? The last dollar wen to the way that math translates from numbers to application.
 Nov 14, 2013
 #2
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You got it right. yay......


Translated using Bing Translator (Spanish to English)
 Nov 20, 2013

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