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csc^2x/cotx=csc(x)sec(x)

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csc^2x/cotx=csc(x)sec(x)

Guest Jan 13, 2015

Best Answer

+130466

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csc^2x/cotx=csc(x)sec(x) working with the LHS

1/sin^x / (cosx /sin x) =

1/ sin^2x (sinx / cos x) =

(1 / sin x) (1 / cos x) =

csc x secx .....and the LHS = RHS

CPhill Jan 13, 2015

1⁺⁰ Answers

+130466

+5

Best Answer

csc^2x/cotx=csc(x)sec(x) working with the LHS

1/sin^x / (cosx /sin x) =

1/ sin^2x (sinx / cos x) =

(1 / sin x) (1 / cos x) =

csc x secx .....and the LHS = RHS

CPhill Jan 13, 2015

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