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How can I find the sum of \(\frac{1}{\sqrt[3]{1}+\sqrt[3]{2}+\sqrt[3]{4}}+\frac{1}{\sqrt[3]{4}+\sqrt[3]{6}+\sqrt[3]{9}}+\frac{1}{\sqrt[3]{9}+\sqrt[3]{12}+\sqrt[3]{16}}\)
\((\mathrm{M}\mathrm{A}\Theta\:1992)\)

 Apr 27, 2023
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The sum is 9^(1/3)/4.

 Apr 27, 2023

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