+130511 Let's divide these first, before we take any roots...so we have
(24x^5y^2) / (3x^2y) =
8*x^3*y and taking the cubed root, we get
(8*x^3*y)^(1/3) = 2x(y)^(1/3) .......... so, only "y" remains under the cubed root.
[Note that we are implying that neither x nor y = 0 in the division !!]
+130511 Let's divide these first, before we take any roots...so we have
(24x^5y^2) / (3x^2y) =
8*x^3*y and taking the cubed root, we get
(8*x^3*y)^(1/3) = 2x(y)^(1/3) .......... so, only "y" remains under the cubed root.
[Note that we are implying that neither x nor y = 0 in the division !!]
