Suppose the polynomial is of degree 3 and satisfies f(3) = 2, f(4) = 4, f(5) = -3, and f(6) = -1. Determine the value of f(0).
+600 These are quite annoying :(
We can let f(x)=ax^3+bx^2+cx+d
We get 27a+9b+3c+d=2, 64a+16b+4c+d=4, 125a+25b+5c+d=-3, 216a+36b+6c+d=-1. We want to find d.
It is a giant bash, but we get d=-238
