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If the initial cost of an object, say gum is 15,and for every new piece of gum its the cost of the last piece times 15%. how much would it be for 200
 Oct 2, 2013

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This is the sum of a geometric progression GP Do you know about those?

a=15
r=1.15
n= 200

s=a ( r^n - 1) / (r-1)

s= 15 * ( 1.15^200 - 1 ) / 0.15

sum of all the costs = 1.37 * 10^14 This is a very big number.
 Oct 3, 2013

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