\((36-25)/(16/(\sqrt64{}))\)
if it's supposed to be the sqaure root of 64 the answer is \(\frac{11}{16/8} = \frac{11}{2}\)
if it's 4 times the sqare root of 6 the answer is \(\frac{11}{4/\sqrt6}=\frac{11\sqrt6}{4}\)
