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\((36-25)/(16/(\sqrt64{}))\)

 Sep 9, 2017
 #1
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if it's supposed to be the sqaure root of 64 the answer is \(\frac{11}{16/8} = \frac{11}{2}\)

if it's 4 times the sqare root of 6 the answer is \(\frac{11}{4/\sqrt6}=\frac{11\sqrt6}{4}\)

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 Sep 9, 2017

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