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In cyclic quadrilateral PQRS,

\(\frac{\angle P}{2} = \frac{\angle Q}{3} = \frac{\angle R}{4}\).

Find the largest angle in quadrilateral PQRS, in degrees.

 Jun 3, 2020
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∠P = 60º       ∠Q = 90º       ∠R = 120º        ∠S = 90º

 

∠P + ∠R = 180º            ∠Q + ∠S = 180º      indecision

 

 Jun 3, 2020
edited by Guest  Jun 3, 2020

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