I'm in Geometry and I'm having trouble with this question - You want to decorate the side of a cylindrical can by coloring a rectangular piece of paper and wrapping it around the can. The paper is 19 cm by 29 cm. Find the two possible diameters to the can to the nearest 0.01 cm. Assume the paper fits exactly.
+9466 There are two ways to wrap the paper around the can.
In case A, the circumference of the can = 19 cm
In case B, the circumference of the can = 29 cm
circumference = π * diameter → diameter = circumference / π
In case A, the diameter = 19 / π ≈ 6.05 cm
In case B, the diameter = 29 / π ≈ 9.23 cm
+9466 There are two ways to wrap the paper around the can.
In case A, the circumference of the can = 19 cm
In case B, the circumference of the can = 29 cm
circumference = π * diameter → diameter = circumference / π
In case A, the diameter = 19 / π ≈ 6.05 cm
In case B, the diameter = 29 / π ≈ 9.23 cm
