d/dx(x/1+x^2) =1-x^2/(1+x^2)^2
I think this must be:
$$\frac{d}{dx}(\frac{x}{1+x^2})=\frac{1-x^2}{(1+x^2)^2}$$
which is correct, but the original needs brackets to make it so:
d/dx(x/(1+x2)) = (1-x2)/(1+x2)2
I do not know what you are asking
but
$$\\\frac{d}{dx}(\frac{x}{1}+x^2)\\\\ =\frac{d}{dx}(x+x^2)\\\\ =1+2x\\\\$$
what is the other half for?
Yes I should have thought of that
Anon you are doing calculus - surely you can put brackets in properly !!