+349 The question isss:
\(\frac{20152016^2}{20152015^2+20152017^2-2}=?\)
Details:
1. This contest will be done daily
2. The first 3 correct answers win
3. The 3 winners will be in the next question
+129852 [20152016^2] / ( [ 20152015^2] + [20152017^2] - 2 ] ) =
[20152016^2] / ( [ 20152016 - 1]^2 + [ 20152016 + 1]^2 - 2 ) =
[20152016^2] /( 20152016^2 - 2(20152016) + 1 + 20152016^2 + 2(20152016) + 1 - 2 ) =
[20152016^2] / [ 2(20152016^2] =
1/2
P.S. - I did NOT "peek" at any other answer before I did mine.....scout's honor !!!!
+349 4. If the amount of people who solved it does not reach 3, the nearest answer will be picked
(sorry I forgot to add this rule...)
Let \(a = 20152016, \) and we have
\(\displaystyle \frac{a^{2}}{(a-1)^{2}+(a+1)^{2}-2}=\frac{a^{2}}{(a^{2}-2a+1)+(a^{2}+2a+1)-2}=\frac{a^{2}}{2a^{2}}=\frac{1}{2}\).
+129852 [20152016^2] / ( [ 20152015^2] + [20152017^2] - 2 ] ) =
[20152016^2] / ( [ 20152016 - 1]^2 + [ 20152016 + 1]^2 - 2 ) =
[20152016^2] /( 20152016^2 - 2(20152016) + 1 + 20152016^2 + 2(20152016) + 1 - 2 ) =
[20152016^2] / [ 2(20152016^2] =
1/2
P.S. - I did NOT "peek" at any other answer before I did mine.....scout's honor !!!!
+118673 Hey guest, thanks for that.
Why don't you join up. We would love that!
We would really like you to present a regular contest question but it would be even better still if it belonged to your username.
If you really do not want to do this for some reason then it would be good if you identified yourself in the first line or heading.
Like for instance.
"Bob's daily question contest."
