http://www.youtube.com/watch?v=zZWd56VlN7w
mean of 56.3% and a standard deviation of 8.1%. in what percent of the game will the success rate be between 50% and 60%
(I am assuming that the scores are normally distributed(
Z 1 = (50-56.3)/8.1 = -0.77778
Z 2 = (60-56.3)/8.1 = 0.45679
Probability that -0.7778 < Z < 0.45679
is give by the area under the normal curve and you have to read it off your z score tables. You will do one side at a time.
The you tube clip above may help you.
+118653 
