David's company reimburses his expenses on food, lodging, and conveyance during business trips. The company pays $60 a day for food and lodging and $0.65 for each mile traveled. David drove 600 miles and was reimbursed $3,390.
Part A: Create an equation that will determine the number of days x on the trip (3 points)
Part B: Solve this equation justifying each step with an algebraic property of equality
+118723 David's company reimburses his expenses on food, lodging, and conveyance during business trips. The company pays $60 a day for food and lodging and $0.65 for each mile traveled. David drove 600 miles and was reimbursed $3,390.
Part A: Create an equation that will determine the number of days x on the trip (3 points)
Each day for x days $60 is spent on food and lodgings, that is a total of 60x dollars
the company pays 65c for each of 600miles that is .65*600=$390
so 390+60x = 3390
If I solve this equation I will have the number of days. 
Part B: Solve this equation justifying each step with an algebraic property of equality
390+60x = 3390 Subtract 390 from both sides
And you can finish it. 
+118723 David's company reimburses his expenses on food, lodging, and conveyance during business trips. The company pays $60 a day for food and lodging and $0.65 for each mile traveled. David drove 600 miles and was reimbursed $3,390.
Part A: Create an equation that will determine the number of days x on the trip (3 points)
Each day for x days $60 is spent on food and lodgings, that is a total of 60x dollars
the company pays 65c for each of 600miles that is .65*600=$390
so 390+60x = 3390
If I solve this equation I will have the number of days.
Part B: Solve this equation justifying each step with an algebraic property of equality
390+60x = 3390 Subtract 390 from both sides
And you can finish it.
