derivative of 0.5 + 1.1e^0.01t

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Guest Mar 31, 2015

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Best Answer

Let f(t) = 0.5 + 1.1e^0.01t

Then f '(t) = (.01)(1.1)e^(.01t) = .011e^(.01t)

CPhill Mar 31, 2015

CPhill · Answer 1 · 2015-03-31T04:19:55

Let f(t) = 0.5 + 1.1e^0.01t

Then f '(t) = (.01)(1.1)e^(.01t) = .011e^(.01t)