i need to figure out the distance travelled by a dragster, using the equation dv/dt=(10t^3)/3-30t^2+60t
+33661 You can do this by integrating twice with respect to t:
acceleration: dv/dt = (10/3)t3 - 30t2 + 60t
velocity: v = ds/dt = (5/6)t4 - 10t3 + 30t2 + constant where s is distance. If we assume the velocity is zero when t = 0, then we just have:
ds/dt = (5/6)t4 - 10t3 + 30t2
Integrate this:
distance: s = t5/6 - (5/2)t4 + 10t3 + constant. If we assume distance is zero when t = 0, then
distance: s = t5/6 - (5/2)t4 + 10t3
.
+33661 You can do this by integrating twice with respect to t:
acceleration: dv/dt = (10/3)t3 - 30t2 + 60t
velocity: v = ds/dt = (5/6)t4 - 10t3 + 30t2 + constant where s is distance. If we assume the velocity is zero when t = 0, then we just have:
ds/dt = (5/6)t4 - 10t3 + 30t2
Integrate this:
distance: s = t5/6 - (5/2)t4 + 10t3 + constant. If we assume distance is zero when t = 0, then
distance: s = t5/6 - (5/2)t4 + 10t3
.
