PLEASE ANSWER THE REMAINING.. :( I;m BEGGING
2. y= (4x2+3x-1) sqrt. 5x-7
3. y= (3x2-4x+4)3 / 2x2-4x+3
4. y= 2x2-5x+7 / sqrt. 4x-5
3. y= (3x2-4x+4)3 / 2x2-4x+3 I'm going to write this in a slightly different manner to avoid using the Quotient Rule....so we have.....
3. y= (3x^2-4x+4)^3 * (2x^2-4x+3)^(-1)
y' = 3(3x^2 - 4x + 4)^2*(6x - 4) * (2x^2 -4x + 3)^(-1) - (2x^2 - 4x + 3)^(-2) (4x - 4)*(3x^2 - 4x + 4)^(3)
Factor
[ (3x^2 - 4x + 4)^2 * (2x^2 - 4x + 3)^(-2)] * [ 3(6x - 4)(2x^2 - 4x + 3) - (4x - 4)(3x^2 - 4x + 4) ] =
[The expression in the second bracket is a little messy to simplify.......I'll use WolframAlpha to help out !!! ]
[(3x^2 - 5x + 3)^2 * (2x^2 - 4x + 3)^(-2)] * [ 24x^3 - 68x^2 +70x - 20]
2. y= (4x2+3x-1) sqrt. 5x-7 I'm assuming that this one is multiplication???...if so, we have
y' = (8x +3)(5x - 7)^(1/2) + (1/2)(5x -7)^(-1/2)(5)(4x^2 + 3x -1)
Factor
(5x - 7)^(-1/2) [ (8x + 3)(5x - 7) + (5/2)((4x^2 + 3x -1) ] =
(5x - 7)^(-1/2) [ 40x^2 - 41x - 21 + 10x^2 + (15/2)x - 5/2 ] =
(5x - 7)^(-1/2) [ 50x^2 - (67/2)x - 47/2)
3. y= (3x2-4x+4)3 / 2x2-4x+3 I'm going to write this in a slightly different manner to avoid using the Quotient Rule....so we have.....
3. y= (3x^2-4x+4)^3 * (2x^2-4x+3)^(-1)
y' = 3(3x^2 - 4x + 4)^2*(6x - 4) * (2x^2 -4x + 3)^(-1) - (2x^2 - 4x + 3)^(-2) (4x - 4)*(3x^2 - 4x + 4)^(3)
Factor
[ (3x^2 - 4x + 4)^2 * (2x^2 - 4x + 3)^(-2)] * [ 3(6x - 4)(2x^2 - 4x + 3) - (4x - 4)(3x^2 - 4x + 4) ] =
[The expression in the second bracket is a little messy to simplify.......I'll use WolframAlpha to help out !!! ]
[(3x^2 - 5x + 3)^2 * (2x^2 - 4x + 3)^(-2)] * [ 24x^3 - 68x^2 +70x - 20]
4. y= 2x^2-5x+7 / sqrt. 4x-5
Again, I'll write this as
4. y= (2x^2-5x+7) * (. 4x-5 )^(-1/2)
y' = (4x -5) *(4x - 5)^(-1/2) - (1/2)(4x - 5)^(-3/2)*(4) * ( 2x^2 - 5x + 7)
(4x - 5)^(1/2) - (4x - 5)^(-3/2)*(2) * (2x^2 - 5x + 7)
Factor
[ (4x - 5)^(-3/2) * [ (4x - 5)^2 - 2(2x^2 - 5x + 7) ]
[(4x - 5)^(-3/2) ] [ 16x^2 - 40x + 25 - 4x^2 + 10x - 14 ]
[(4x - 5)^(-3/2)] [ 12x^2 - 30x + 11]