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avatar+322 

Differentiate.

 

f(x)= sec(θ) tan(θ)

 

f'(x)=

 Feb 21, 2019
edited by Ruublrr  Feb 21, 2019
 #1
avatar+103097 
+2

f(x)  =  sec(θ) tan(θ) 

 

f ' (x) = sec(θ)*tan (θ) * tan (θ)  + sec(θ)sec^2(θ)  =   sec(θ) [ tan^2 (θ) + sec^2 (θ) ]

 

Note : other answers are possible 

 

 

cool cool cool

 Feb 21, 2019
 #2
avatar+322 
+1

I have no clue what the answer is.  I got a different answer and I put the answer you got in and it still says it's wrong.  I'm assuming there must be one way they will take the answer. 

Ruublrr  Feb 21, 2019
 #3
avatar+322 
+1

Nevermind.  I'm the biggest idiot ever.  I had to replace "x" with "theta" because I put x's wherever there was a theta.

Ruublrr  Feb 21, 2019
edited by Ruublrr  Feb 21, 2019
 #4
avatar+103097 
+3

Here are some other possibilities using WolframAlpha

 

https://www.wolframalpha.com/input/?i=derivative+%5B+sec+x+*+tan+x+%5D

 

You might try some of the other ones....!!!

 

 

cool cool cool

CPhill  Feb 21, 2019
 #5
avatar+103097 
+2

LOL!!!....mystery solved !!!!

 

 

cool cool cool

CPhill  Feb 21, 2019

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