what is the sum of one seventh and one thrid and one forth
\(\frac{1}{7} + \frac{1}{3}+\frac{1}{4} =\frac{12}{84}+\frac{28}{84}+\frac{21}{84}= \frac{12+28+21}{84} = \frac{61}{84}\)
I used 84 as the denominator, as it was the Least Common Denominator of 7, 3, and 4.
+633 
