detailed solution needed

$$\\10 logx=-62\\ logx=-6.2\\ 10^{logx}=10^{-6.2}\\ x=10^{-6.2}\\$$

$${{\mathtt{10}}}^{\left(-{\mathtt{6.2}}\right)} = {\mathtt{0.000\: \!000\: \!630\: \!957\: \!344\: \!5}}$$

On the web2 calc you do not need to do all that - it will do it for you.  Tricky isn't it.   

$${\mathtt{10}}{\mathtt{\,\times\,}}{log}_{10}\left({\mathtt{x}}\right) = -{\mathtt{62}} \Rightarrow {\mathtt{x}} = {{\mathtt{e}}}^{{\mathtt{\,-\,}}\left({\frac{{\mathtt{31}}{\mathtt{\,\times\,}}{ln}{\left({\mathtt{10}}\right)}}{{\mathtt{5}}}}\right)} \Rightarrow {\mathtt{x}} = {\mathtt{0.000\: \!000\: \!630\: \!957\: \!344\: \!5}}$$