Determine k so that the given line will have to given slope.
1) 12x - ky = 5, m = 3
2) (-4,k) & (-1,3k), m = 4
3) kx + 2y = 6, m= k+1
4) (k+1, k) & (-3, 2), m= 2
1) 12x - ky = 5, m = 3
Rewrite as ky = 12x - 5 .....divide both sides by k....... y = (12/k) - 5/k ....and the slope is determined by the coefficient on x....so..... m = 3 = 12/k and it's clear that k must be 4
Heres the graph of 12x - 4y = 5 ....... https://www.desmos.com/calculator/ibpwuqrgk0
2) (-4,k) & (-1,3k), m = 4
So we have.....
[3k - k] / [ -1 - (-4)] = 4
[2k] / [3 ] = 4 multiply both sides by 3
2k = 12 divide both sides by 2
k = 6