Determine the common ratio and find the next four terms of the geometric sequence.

a^(-6),a^(-2), a^2

Guest Jun 2, 2015

#1**+15 **

Well, the common ratio in a geometric sequence is what your multiplying each of these numbers by to get the next number. So, in this case, the comon ratio would be a^4, because whenever you multiply two numbers with exponets *and they have the same base *you add the exponets. for example,

$$a^{-6} \;\times\;a^{4}\;=\;a^{-6+4}\;=\;a^{-2}$$

And to find the next four terms, you would just multiply a^2 by a^4 and that would be your next term, then you would multiply that answer by a^4 and so on.

Try it out and let me know if you can get it. If you can't post again and me or another forum member should be able to help you out :)

NinjaDevo Jun 3, 2015

#1**+15 **

Best Answer

Well, the common ratio in a geometric sequence is what your multiplying each of these numbers by to get the next number. So, in this case, the comon ratio would be a^4, because whenever you multiply two numbers with exponets *and they have the same base *you add the exponets. for example,

$$a^{-6} \;\times\;a^{4}\;=\;a^{-6+4}\;=\;a^{-2}$$

And to find the next four terms, you would just multiply a^2 by a^4 and that would be your next term, then you would multiply that answer by a^4 and so on.

Try it out and let me know if you can get it. If you can't post again and me or another forum member should be able to help you out :)

NinjaDevo Jun 3, 2015