Determine the equation of a line parallel to −6x + 3y = −18 with the same x-intercept as the line defined by 14x + 7y − 14 = 0.

-6x + 3y  = -18

3y = 6x -18      divide through by 3

y = 2x - 6

The slope of the line we're looking for = 2

x intercept  of  14x +7y - 14  =0

Let y = 0

14x - 14 =  0

14x  =14    divide through by 14

x =1

So.....we have the point (1,0)

Equation of line

y = 2 (x -1)

y = 2x  - 2

2x - y  - 2   =  0