cos2x - sinx = 0
(1 - 2sin^2 x) - sin x = 0 multiply through by -1
2sin^2 (x) + sin x - 1 = 0 factor
(2sin x - 1) (sin x + 1) = 0
Set each factor to 0 and solve for x
2sinx - 1 = 0
2sin x = 1
sin x = 1/2
And this happens at x = pi/6 + 2pi*n and x = 5pi/6 + 2pi*n where n is an integer
Also
sinx + 1 = 0
sin x = -1
And this happens at x = 3pi/2 + 2pi*n where n is an integer