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determine the general solution for sin 2x=1

nlbradshaw0430  Apr 13, 2017
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sin (2x)  = 1

 

Let   2x  = θ

 

sin (θ)  = 1      at     θ  =  pi/2  + 2pi*n

 

So

 

2x  =   pi/2  + 2pi*n         divide by 2

 

x  =   pi/4  + pi* n             where n is an integer

 

 

cool cool cool

CPhill  Apr 13, 2017
edited by CPhill  Apr 13, 2017

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