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Determine the rate of depreciation : F=P(1-i)^t 400000=208802.50(1-i)^4. I'm looking for I in this equation.

 Oct 14, 2014

Best Answer 

 #1
avatar+130511 
+5

400000=208802.50(1-i)^4       divide both sides by 208802.50

(400000/208802.50) = (1 - i)^4   take the log of both sides

log(400000/208802.50) = log(1-i)^4     and by a log property, we can write

log(400000/208802.50)= 4log(1-i)        divide both sides by 4

log(400000/208802.50)/ 4  =  log(1 - i)         and in exponential form ,we have

10 ^ (log(400000/208802.50)/ 4 ) =  1 - i     and rearranging, we have

i = 1 - 10 ^ (log(400000/208802.50)/ 4 ) = -(3/17)

Note that this makes mathematical sense, because the expression (1 - i) = (1 - (-3/17)) = (1 + 3/17) which is greater than 1. (I just wonder if this equation actually deals with depreciation. This looks more like a "growth" equation, rather than a "decay" equation.)

 

 Oct 14, 2014
 #1
avatar+130511 
+5
Best Answer

400000=208802.50(1-i)^4       divide both sides by 208802.50

(400000/208802.50) = (1 - i)^4   take the log of both sides

log(400000/208802.50) = log(1-i)^4     and by a log property, we can write

log(400000/208802.50)= 4log(1-i)        divide both sides by 4

log(400000/208802.50)/ 4  =  log(1 - i)         and in exponential form ,we have

10 ^ (log(400000/208802.50)/ 4 ) =  1 - i     and rearranging, we have

i = 1 - 10 ^ (log(400000/208802.50)/ 4 ) = -(3/17)

Note that this makes mathematical sense, because the expression (1 - i) = (1 - (-3/17)) = (1 + 3/17) which is greater than 1. (I just wonder if this equation actually deals with depreciation. This looks more like a "growth" equation, rather than a "decay" equation.)

 

CPhill Oct 14, 2014

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