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Determine whether each function is linear, quadratic or exponential. Write an equation for the model that best fits the data. x:-2,-1,0,1,2;

y:1,.25,0,.25,1

Whiz333  Apr 11, 2017
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Let's see.....we have the points

 

(-2, 1) , (-1, .25), (0, 0), (1, .25) and ( 2,1)

 

Not linear or exponential.....!!!

 

(0,0)  is the vertex of the quadratic.....  [ a parabola ]

 

So the form will be

 

y  = ax^2      and using one of the other points to solve for "a", we have

 

1  = a(-2)^2    →  1  =  =4a   →   a  = 1/4

 

So....our function is :    y  = (1/4)x^2

 

Look at the graph here  : https://www.desmos.com/calculator/owwsbihvun

 

 

cool cool cool  

CPhill  Apr 11, 2017

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