Determine whether each function is linear, quadratic or exponential. Write an equation for the model that best fits the data. x:-2,-1,0,1,2;

y:1,.25,0,.25,1

Whiz333
Apr 11, 2017

#1**+1 **

Let's see.....we have the points

(-2, 1) , (-1, .25), (0, 0), (1, .25) and ( 2,1)

Not linear or exponential.....!!!

(0,0) is the vertex of the quadratic..... [ a parabola ]

So the form will be

y = ax^2 and using one of the other points to solve for "a", we have

1 = a(-2)^2 → 1 = =4a → a = 1/4

So....our function is : y = (1/4)x^2

Look at the graph here : https://www.desmos.com/calculator/owwsbihvun

CPhill
Apr 11, 2017