+0  
 
0
871
1
avatar+4 
How do you determine zeros for this?

x^3-3x^2-16x+48
 May 12, 2012
 #1
avatar+3146 
0
[input]x^3-3x^2-16x+48=0[/input]
 May 13, 2012

1 Online Users

avatar