**I need help with #1.b)**

**I got** tan θ = -1.7, with θ = -59.5°. I got tan θ right, while θ = 120.5° in the textbook.

How should I get an answer of 120.5°?

Guest Jan 30, 2019

#1**+1 **

You have the correct idea.....

The angle that you found is a reference angle of 59.5° in the 4th quadrant

But....If you look carefully, you will note that the measure of this angle plus the measure of θ = 180°

So....to find θ....we have that

59.5 + θ = 180 subtract 59.5 from both sides

θ = 120.5°

CPhill Jan 30, 2019