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I have to determine the smallest integer \(x\) that satisfies the given inequality:

\({2^{\sqrt{2x}} > 34}\)

 

\(x\) > _______

 

How would I find the smallest integer?

 Aug 7, 2020
 #1
avatar+32141 
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Like so:

So x = 13

 Aug 7, 2020

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