+0  
 
0
870
1
avatar

I have to determine the smallest integer \(x\) that satisfies the given inequality:

\({2^{\sqrt{2x}} > 34}\)

 

\(x\) > _______

 

How would I find the smallest integer?

 Aug 7, 2020
 #1
avatar+33654 
+2

Like so:

So x = 13

 Aug 7, 2020

0 Online Users