Develop the formula for the sum of the first n counting numbers.

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S= 1 + 2 + 3 + ... + (n-2) + (n-1) + n

Find the sum of the first 499 counting numbers

Guest Feb 19, 2020

Hypotenuisance · Answer 1 · 2020-02-19T01:36:24

Thanks for the A2A!

Sum = (n*(n+1))/2

499*500 = 249500

249500/2 = 124750

Cheers!