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Develop the formula for the sum of the first n counting numbers. 

S= 1  +    2   +   3   + ... +   (n-2)    +    (n-1)   +   n 

 

Find the sum of the first 499 counting numbers

 Feb 19, 2020
 #1
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Thanks for the A2A!

 

Sum = (n*(n+1))/2

 

499*500 = 249500

 

249500/2 = 124750

 

Cheers!laugh

 Feb 19, 2020

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