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(3x^3-4) / (x+3)

 Apr 5, 2016

6+0 Answers

 #1
avatar+188 
0

Just remove the parentheses...

ANSWER: 3x^3 - 4 / x + 3

 Apr 5, 2016
 #2
avatar+545 
0

I don't think so it' has to be mroe than that.

Katie-Leigh  Apr 5, 2016
 #4
avatar+188 
0

https://www.symbolab.com/solver/algebra-calculator/%5Cleft(3x%5E%7B3%7D-4%5Cright)%20%5Cdiv%20%5Cleft(x%2B3%5Cright)/?origin=button 

Visit this link...

Carpe♥Diem  Apr 5, 2016
 #3
avatar
0

[(3x^3) / (x+3)]  -  [4 / (x+3)], OR,

 

3x^2 - 9x - [85/(x+3)] + 27, OR,

 

3 x^3-4 = (3x^2 - 9x + 27) × (x+3)+-85 [Quotient and Remainder]

 Apr 5, 2016
 #5
avatar+129852 
0

We need to use polynomial long division here, Katie-Leigh

 

              3x^2   - 9x    +  27

 

x + 3    [  3x^3  + 0x^2  +  0x   -  4   ]

               3x^3  + 9x^2

              ______________________

                           -9x^2   + 0x

                           -9x^2  - 27x

                           -----------------

                                        27x - 4

                                        27x + 81

                                        ------------

                                               -85

 

So the result   is     [ 3x^2 - 9x + 27]  R  -85/(x + 3)

 

 

 

cool cool cool

 Apr 5, 2016
 #6
avatar+545 
0

okay thanks CPhill.

Katie-Leigh  Apr 6, 2016

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