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what expression can i do for the numbers 5 4 3 2 1 to equal 0

Guest Sep 21, 2017
 #1
avatar+109 
+3

Because 5+1=2+4=6, then we can make them subtract from each other and multiply it to the remaining numbers to get 0.

 

3*[(5+1)-(4+2)]=0

Jeff123  Sep 21, 2017
 #2
avatar+2083 
+2

Here's another solution!

 

\(4^{2+3-5}-1=0\)

\(4^2-5*3-1=0\)

\(\frac{4*3}{2}-5-1=0\)

\(\frac{4+1}{5}-3+2=0\)

 

These are a few possibilities that I came up with.

TheXSquaredFactor  Sep 22, 2017
 #3
avatar+7096 
+1

Also..

 

5 * 4 * (3 - 2 - 1)

 

If you want to keep them in that order. smiley

hectictar  Sep 22, 2017

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