The width of the rectangles is 50% its length. Given that the perimeter of 3 such rectangles is 90 cm, find the length of 1 rectangle.
+201 If the perimeter of 3 rectangles is 90cm, the perimeter of 1 is 30.
If the width of the rectangle is x, than the whole rectangle would be 6 x.
30=6x, so x=5
the length of one rectangle is 10
your welcome :)
+201 sorry I didnt explain it in too much detail I didnt have much time.
I hope you understand it.
+201 This might be a better visual that made!
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|30, or 6x | x
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2x
+876 Honestly, I think @mathisopandcool's solution is nice and clear enough. @guest, it is not his/her fault if YOU can't understand a thing. Why are you being rude?
+876 The width of the rectangles is 50% its length. Given that the perimeter of 3 such rectangles is 90 cm, find the length of 1 rectangle.
Let l be the length
Let w be the width
w=1/2 l (1)
2(l+w) * 3 = 90 (2)
Simplifying (2): 2l+2w=30
l+w=15 (3)
(1) & (2) : 3/2 l = 15
1/2 l = 5
L = 10
Length is 10.
Enjoy you ungrateful guest.
