+0  
 
0
94
2
avatar

A 6-sided fair die is rolled 10 times. What is the probability of a third 6 on the 10th roll? Thank you.

 Oct 21, 2018

Best Answer 

 #1
avatar+3567 
+2

\(P[\text{3rd 6 on roll 10}]=P[\text{2 6's in 9 rolls and a 6 on the 10th roll}=\\ \dbinom{9}{2}\left(\dfrac 1 6\right)^2 \left(\dfrac 5 6\right)^7 \cdot \dfrac 1 6 = \dfrac{78125}{1679616}\)

.
 Oct 21, 2018
 #1
avatar+3567 
+2
Best Answer

\(P[\text{3rd 6 on roll 10}]=P[\text{2 6's in 9 rolls and a 6 on the 10th roll}=\\ \dbinom{9}{2}\left(\dfrac 1 6\right)^2 \left(\dfrac 5 6\right)^7 \cdot \dfrac 1 6 = \dfrac{78125}{1679616}\)

Rom Oct 21, 2018
 #2
avatar+95000 
0

Thanks Rom,

I don't think I would have thought to do that.  laugh

Melody  Oct 21, 2018

6 Online Users

avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.