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Okay so I did the dot product with a and b and I got (2,-10,-1). 

Then: √(2)^2+(-10)^2+(-1)^2) and I get 

A = √(105). Am I correct?

 May 13, 2018
 #1
avatar+23040 
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Did I do it right?

 

You mean the vector cross product!

 

 

\(\begin{array}{|rcll|} \hline A &=& \sqrt{2^2+(-10)^2+(-7)^2} \\ A &=& \sqrt{4+100+49} \\ \mathbf{A} & \mathbf{=} & \mathbf{\sqrt{153}} \\ \hline \end{array}\)

 

laugh

 May 14, 2018
edited by heureka  May 14, 2018

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