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# Didn't understand concept plz help with HW

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1) Compute $$sin^{-1} \left(\sin \left(\frac{7\pi}6\right)\right).$$

2) Compute $$\sin\left(\arccos\left(\frac{\sqrt{5}}3\right)\right).$$

3) Compute $$\arccos\left(\frac{\sqrt{3}}{2}\right).$$

Oct 5, 2019

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1 - Do what is inside brackets first.
Sin(7pi/6) = - 1/2 - This is in radians.

Then take the arcsin of - 1/2 = - pi/6

2 - Do the same thing here.
Arccos(sqrt(5) / 3) = 0.729727656- This is in radians.
Take its sin(0.729727656) = 2/3

3 - This is straightforward.
Arccos(sqrt(3) / 2) =pi / 6

Oct 5, 2019