differentiate y=In tan^2x
\(y=ln(tan^2x)\\ \frac{dy}{dx}=\frac{2tanxsec^2x}{tan^2x}\\ \frac{dy}{dx}=\frac{2sec^2x}{tanx}\\ \frac{dy}{dx}=\frac{2cosx}{sinxcos^2x}\\ \frac{dy}{dx}=\frac{2}{sinxcosx}\\ \frac{dy}{dx}=\frac{4}{sin2x}\\ \frac{dy}{dx}=4cosec2x\\ \)
