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differentiate

 1⁄3x^6(x^2-3)

 Aug 9, 2015

Best Answer 

 #1
avatar+95350 
+8

 1⁄3x^6(x^2-3)

 

$$\\y= 1/3x^6(x^2-3)\\\\
y=\frac{x^6}{3}\times (x^2-3)\\\\
y=\frac{x^8}{3}-x^6\\\\
\frac{dy}{dx}=\frac{8x^7}{3}-6x^5\\\\$$

.
 Aug 9, 2015
 #1
avatar+95350 
+8
Best Answer

 1⁄3x^6(x^2-3)

 

$$\\y= 1/3x^6(x^2-3)\\\\
y=\frac{x^6}{3}\times (x^2-3)\\\\
y=\frac{x^8}{3}-x^6\\\\
\frac{dy}{dx}=\frac{8x^7}{3}-6x^5\\\\$$

Melody Aug 9, 2015
 #2
avatar+414 
+3

1⁄3x^6(x^2-3) \\y= 1/3x^6(x^2-3)\\\\ y=\frac{x^6}{3}\times (x^2-3)\\\\ y=\frac{x^8}{3}-x^6\\\\ \frac{dy}{dx}=\frac{8x^7}{3}-6x^5\\\\ Like melody's answer

 Aug 9, 2015

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